Split string by space don´t work. How do I find the character?

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1

I have a name stored as a variabel (as a string), it’s both first and lastname separated by space. I now try to break them a part in to two variables, firstname and lastname. But uipath don´t reqonice the space, I can´t use mystring.Split(" ".ToCharArray)(2).ToString

How can I find out what character other then space it can be?

2

mystring.split(" "c).toArray()(2)

3

You can split it this way for any whitespace, where MyVar is your string variable you’re trying to split.

System.Text.RegularExpressions.Regex.Split(MyVar, "\s+")

1 Like
4

But I think that your array only contains two values (firstName, lastName), so your array only has 0 and 1 position.

fName = mystring.split(" “c).toArray()(0)
lName = mystring.split(” "c).toArray()(1)

5

Hi @Zlotzky,

Try this

FirstName = Text.Split(New Char() {" “c}).ToArray()(0)
LastName = Text.Split(New Char() {” "c}).ToArray()(1)

image

6

Hi @Zlotzky

please check this Image

image
image485×515 9.77 KB

image

image

FirstName = Fullname var.split(" “c)(0)
LastName = Fullname var.split(” "c)(1)

Regards,
Gulshiyaa

7

Thanks but I´d tried with that. the problem is that it does not reconize the space so even with split(" "c) it remains as both first and lastname

8

image

9

See my solution. It accounts for any whitespace (tabs, newlines, spaces, etc.). It also accounts for multiple spaces, so string "hello there, friend" would split to {“hello”, “there,”, “friend”} despite the variable number of spaces.

10

image
image1226×584 119 KB

Here´s a pict, I´t don´t split the space.

11

I get a error message that I´m not certain of. se pict above in message no 7

12

@Zlotzky
The error message when applying Anthony_Humphries answer shows that your variable type should be an Array of String rather than simply a String.

If you want to assign directly the firstname and lastname values, please apply proper index:

System.Text.RegularExpressions.Regex.Split(MyVar, “\s+”)(0)
System.Text.RegularExpressions.Regex.Split(MyVar, “\s+”)(1)

14

@msan thanks!

15

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