Error is displayed when trying to create 16 digit fixed length random number

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1

Hi all,
Error is displayed when trying to create 16 digit fixed length random number
I am assigning an int variable as:
intRandomNumber= New Random() Next(1000000000000000,9999999999999999)

But its showing error as ‘Constant expression not representable in integer’

Even if i selected variable type as ‘Double’ it’s giving me similar error.

Can anyone kindly help.

Thank you

2

Hi
image
The next method accepts only Int32 values. Largest int32 number have only 10 digits.

But you can split generating into 2 parts:
generate first 8 digits:

random.Next(10000000,99999999)

Convert this number to decimal, multiple by 10000000 and add to second 8-digits random number:

random.Next(00000000,99999999)

Now you should have 16-digits random value from 1000000000000000-9999999999999999.
I recommend to use decimal instead of double in this case (double have 15-17 digits precision)

1 Like
3

Hi @Deepa_Madkar

To generate a 16-digit random number, you can use a different data type, such as a Long or a Decimal , which can represent larger values. Here is an example of how you could generate a 16-digit random number using a Long data type.

Random random = new Random()
long intRandomNumber = random.Next(1000000000000000L, 9999999999999999L)

Thanks!!!

4

Thanks @Konrad_Mierzwa for the reply.
This alternate method is good. Thank you for bringing it up

5

Hi @Kaviyarasu_N thanks for the reply.
long datatype is variable type 'Microsoft.Visualbasic.compilerservices.longtype ??

Also how to store this in variable?
Random random = new Random()
long intRandomNumber = random.Next(1000000000000000L, 9999999999999999L)

Can you please tell?

Thank you in advance

6

full name of long type is ‘System.Int64’

You can use assign activitiy:
image
where random variable is of type System.Random

7

Thanks @Konrad_Mierzwa for the reply.
I tried as you told.
But it’s still giving me same error as mentioned in my query
I am using int64 as variable type for the number but still same issue

8

Hi,

If you can use Windows project (or cross platform project) (this means .Net6), NextInt64 method helps you.

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image1439×655 41 KB 

longVar = rnd.NextInt64(1000000000000000L,9999999999999999L)

Regards,

9

Thank you @Yoichi for the reply.
Because of company policy restrictions i cannot use any other cross platform.

But thank you for providing the reason behind

10

Hi,

In this case, we can achieve it using two Random.Next method as the following.

image
image931×783 29.9 KB 

rnd = New Random()
v1 = rnd.Next(0,99999999)
v2 = rnd.Next(10000000,99999999)

then

Int64.Parse(v2.ToString+v1.ToString)

Sample20221228-7L.zip (2.2 KB)

Regards,

11

Yes this alternative solution works @Yoichi .
Thank you

12

Hi,

Sorry, but need to modify it as the following. It’s better to add PadLeft method as the following, because v1 might has less 8 digits.

Int64.Parse(v2.ToString+ v1.ToString.PadLeft(8,"0"c))

Regards,

13

Hi @Yoichi ,
how do I know, if I have .Net6 or how can I use it (if our company policy allows)?

Regards,
Moritz

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HI,

We can check it in project panel or bottom-right corner of Studio.

image
image450×623 25.1 KB

it depends on Compatibility which we choose in create the project.

Regards,

1 Like
15

Hi @Yoichi ,

thanks for your response.
I can’t choose when starting a new process and I don’t see in studio, there is nothing in brackets behind ‘Dependecies’.
Maybe it is due to company policy or it is because we still have an old version of studio: 2019.10

So I will use the other solution, thanks!

Regards,
Moritz

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