Hi, I have been seen in older videos of UiPath, it’s saying after using DeSerialize JSON Activity and converting string into JSON type. If we want to see the data into the JSON Variable , Then if we just put simply in message box JSONObjVariable(“ObjectName”). It will showup the value. But in Rece…

@Salman_Faries Newtonsoft.Json.Linq.Jobject [image]

@Salman_Faries Did you try like this jsonObjVariable(“ObjectName”).ToString()

Hi @Salman_Faries jsonObject(“ObjectName”).ToString() Hope it helps!!

Thanks for your reply guys. I tried it, But it still shows the same error! (Not Working)

@Salman_Faries May i know what is the error displaying send a ss if possible

@Salman_Faries [image] API - DeSerialize JSON -UiPath Studio Studio Hi @Salman_Faries Try this JSONObjVariable.GetValue(“ObjectName”).ToString() I hope it works!! did you try this?

@Salman_Faries Just one more check to do …in the deserialize json activity check if the type argument is set to jObject…if not set it to Jobject…then it should be working Cheers

Will you please say, to set jobject. What is the exact type i need to give?

Attaching ScreenShot here, [image]

API - DeSerialize JSON -UiPath Studio

Help Studio

lrtetala (Lakshman Reddy) July 15, 2023, 3:41pm 6

Hi @Salman_Faries

Try this

JSONObjVariable.GetValue(“ObjectName”).ToString()

I hope it works!!

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API - DeSerialize JSON -UiPath Studio

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