Split the string data

[Aarthy1 (Aarthy)]

Hai

Here is the string variable " (6863577)FJIDXFHHDDDDFF ". This is the input, i need “FJIDXFHHDDDDFF” As the output.

[rlgandu (Rajyalakshmi Gandu)]

@Aarthy1

Use regex

System.Text.RegularExpressions.Regex.Match(Input,“(?<=))[A-Z]+”).Value

[mkankatala (Mahesh Kankatala)]

Hi @Aarthy1

- Assign -> StrVar = "(6863577)FJIDXFHHDDDDFF"
- Assign -> StrVar = StrVar.Split(")")(1).toString.trim

Check the below image for better understanding

You can use the below regular expression to extract the output.

System.Text.RegularExpressions.Regex.Matches(yourstringinput.ToString,“((?<=\))[A-Z]+)”)

Hope it helps!!

[lrtetala (Lakshman Reddy)]

Hi @Aarthy1

(?<=\)).*(?= ")

[pravallikapaluri]

Hi @Aarthy1

string input = "(6863577)FJIDXFHHDDDDFF";
string output = input.Substring(input.IndexOf(")") + 1)

Hope it helps!!

[tazunnisa.badavide (Taj)]

[Vikas_M]

@Aarthy1

" (6863577)FJIDXFHHDDDDFF ". This is the input, i need “FJIDXFHHDDDDFF”

Hey @Aarthy1 ,
You can use input.Split(")"c)(1)

So basically the above code will split the string on the basis of closing parenthesis , i.e. “)”

The output of normal split is a collection, but we want a string after the closing parenthesis so we write (1) to access the second element (index 1) of the array that results from the split. Arrays

below is the output

Hope it helps you

[Mohammad.Fuad]

If your input string is the same format as (6863577)FJIDXFHHDDDDFF , you can [A-Z]+ regex expression

outputString = regex.match(inputString,“[A-Z]+”)

[vidyasreeb (SVR)]

@Aarthy1

You can try as below

Cheers !