SAP-Fiori

[happyfeat87 (Kowalski)]

Hello all This is the text i have

Error Message Bar Parked document 1710 DSD does not exist
Parked document 1710 DSD does not exist

But i need Error and Parked document 1710 DSD separately.

Thank you.

[Tapan_Behera1 (Tapan Behera)]

Hi @happyfeat87 are you want to extract Error and Parked document 1710 DSD from the above text?

[Gokul001 (Gokul Balaji)]

HI @happyfeat87

Try with this Regex Expression

System.Text.RegularExpressions.Regex.Match(YourString,"(Err)\S.*(?=\sdoes)").Tostring

[Gokul001 (Gokul Balaji)]

Hi @happyfeat87

System.Text.RegularExpressions.Regex.Match(YourString,"^Error").Tostring

Output -> Error

[Gokul001 (Gokul Balaji)]

HI @happyfeat87

System.Text.RegularExpressions.Regex.Match(YourString,"(?<=Message\sBar\s)(\S.*)(?=\sdoes)").Tostring

Output -> Parked document 1710 DSD

Regards
Gokul

[Sudharsan_Ka]

HI @happyfeat87

Checkout this expression

System.Text.RegularExpressions.Regex.Match(str,"(?<=Error Message Bar\s).*(?=\sdoes)").tostring

if you want to separate the lines try this

For first line

System.Text.RegularExpressions.Regex.Split(str,"\n")(0)

For second line

System.Text.RegularExpressions.Regex.Split(str,"\n")(1)

Regards
Sudharsan

[happyfeat87 (Kowalski)]

Yes.
And in future it could be like

Success Message Bar Parked document XXXX is success
Parked document XXXX success

[Gokul001 (Gokul Balaji)]

Hi @happyfeat87

System.Text.RegularExpressions.Regex.Match(YourString,"^Error|^Success").Tostring

Regards
Gokul

[Gokul001 (Gokul Balaji)]

HI @happyfeat87

System.Text.RegularExpressions.Regex.Match(YourString,"(?<=Message\sBar\s)(\S.+)(?=\sis|\sdoes)").Tostring

[happyfeat87 (Kowalski)]

Thank you.
But the challenge is that text would be changing dynamically.
For example.
In future It could be
Success Message Bar Parked document XXXX is success
Parked document XXXX success

But the position of the words Message Bar will be same.

[Gokul001 (Gokul Balaji)]

@Gokul001

System.Text.RegularExpressions.Regex.Match(YourString,"^Error|^Success").Tostring

@Gokul001

System.Text.RegularExpressions.Regex.Match(YourString,"(?<=Message\sBar\s)(\S.+)(?=\sis|\sdoes)").Tostring

Check out this expression @happyfeat87

[Tapan_Behera1 (Tapan Behera)]

@happyfeat87 Okay use these regex pattern

1. (?:^error|success)
2. (?:parked\sdocument\s\d*\sdsd)

(?:parked\sdocument\s\d*\sdsd)|(?:^error|success)

[Sudharsan_Ka]

@happyfeat87

Checkout this for your status success or error

Split(System.Text.RegularExpressions.Regex.Split(str,"\n")(0)," ")(0)

For parked document

System.Text.RegularExpressions.Regex.Match(str,"(?<=Bar\s)Parked document.*(?=\sis|\sdoes)").tostring

[happyfeat87 (Kowalski)]

@Gokul001

@Gokul001

System.Text.RegularExpressions.Regex.Match(YourString,"^Error|^Success").Tostring

Thank you for your response.

I tried both the expressions.
1st one works fine.
But the second expression is not giving expected result.

[Gokul001 (Gokul Balaji)]

What is Input for the Second method? @happyfeat87

Can you share with us?

[happyfeat87 (Kowalski)]

Thanks for the response.

System.Text.RegularExpressions.Regex.Match(str,"(?<=Bar\s)**Parked documen**t.*(?=\sis|\sdoes)").tostring

But text in bold will be changing.

[Sudharsan_Ka]

@Sudharsan_Ka

System.Text.RegularExpressions.Regex.Split(str,"\n")(1)

Try this @happyfeat87

[happyfeat87 (Kowalski)]

@Sudharsan_Ka

System.Text.RegularExpressions.Regex.Split(str,"\n")(1)

Perfect!!

Thanks.