How to remove duplicates from integer array using for each loop(Without using Distinct or LINQ)
Iterating through and checking each value in a for each statement works, but if you are looking at a large set of data it will take a long time. Instead, you could utilize LINQ to accomplish the task in a more efficient manner all in a single assign activity.
arr.GroupBy(Function(i) i ).Where(Function(g) g.Count() =1).Select(Function(s) s(0)).toArray()
Also another method
Assuming this is an array <T>
(such as integer)
assign newArray = array.Distinct().ToArray()
Hi nikhil.girish
Thank you for your answer.
Can you show me how to do it using for each loop. I want to use newArray as empty array. Then want to check one by one and assign it to the empty array using IF condition.
intArray = {1,2,3,3,2,4,5,5,1}
newArray = {}
Hi Nithinkrishna
Thank you for your answer.
Can you show me how to do it using for each loop. I want to use newArray as empty array. Then want to check one by one and assign it to the empty array using IF condition
intArray = {1,2,3,3,2,4,5,5,1}
newArray = {}
we would recommend to go for the oneliner with the distinct()
a for each approach would look like this:
distinctValues | List(of Int32) = new List(Of Int32)
For each | item in intArray - TypeArgument: Int32
- If Activity: Not distinctValues .Contains(item)
- then Branch: Add to collection Activity
On the end we can convert the list into an array by newArray = distinctValues .ToArray
You can do the distinct functionality and then assign the same array to newly created array variable.
Thanks
here you go
as PPR suggested even i do recommend you to go with one liner
Thanks