str = “test1”+environtment.newline+“test2”
arr_str = str.split(environtment.newline+“test2”.tochararray)
arr_str(0)
the result is still:
test1
test2
what i want is:
test1
space works as enter as well?
i will try first
Assign: arr_str = inputText.Split({Environment.NewLine}, StringSplitOptions.RemoveEmptyEntries)
Hi @wija
Use the below split condition
=> Assign -> StrVar = "Test1"+Environment.NewLine+"Test2"
=> Assign -> Output = StrVar.Split(vbcrlf.ToCharArray).First
Check the below image for better understanding
Hope it helps!!
strD=strD.Split(
new string[ ] { Environment.NewLine },
StringSplitOptions.None)[0]
Hi @wija
input="test1"+Environment.NewLine+"test2"
output=input.Split(Environment.NewLine.ToCharArray).First
both input and output variables are of Datatype System.String
Hope it helps!!
can u try with this requirement inside the split?
environtment.newline+“test2”.tochararray
Hi,
Your expression seems no problem to return just “test1” as the following.
Can you share actual workflow (Screenshot or file)?
Regards,
Hi @wija
It will return tes1 as your output. Check the below image for better understanding.
Regards
i don’t know, i try my expression in new blank project and seems nothing wrong & works the way i want.
but in my other project, using same code, it is not giving the value i want =_=
only (environment.newline.tochararray).first is giving value i want, while
(environment.newline+“the text”.tochararray).first is not giving value i want
i even use message box before split & after split to check the result, the result both message box are same nothing changed. so annoying
Hi,
environment.newline.tochararray returns char array : {chr(13), chr(10)} This split the string by chr(13) or chr(10)
On the other hand, environment.newline+“the text”.tochararray returns single string : "\r\nthe text" This split the string by the single string.
(note: \r is chr(13), \n is chr(10))
From the above point, Is here any reason to unable to split?
Regards,
hmm, based on this…
is there an idea to make it splitted as {“\r”, “\nthe text”}
?
The following will work. Can you tryy this?
yourString.Split({chr(13),chr(10)+"the text"},StringSplitOptions.RemoveEmptyEntries)
Regards,
this code won’t give exception error regardless any kind of string value in a string variable?
i mean, will this code become problematic in future?
Hi,
This expression returns one or more string item as string array.
So, it doen’t throw exception itself. However, as there might not be 2nd or more items, it might be caused by error if access 2nd item, in later process, for example.
Regards,
well, hmm
marked as solution then.
thank you.
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