How to initialize Array of dictionary?

[Jon_G]

Hi there,

How do you initialize an Array of Dictionary?

I have tried New Dictionary(Of string,string){} but this displays as an error. Have tried other variations but no luck.

[ppr (Peter Preuss)]

@Jon_G

Array of Dictionary?

new Dictionary(Of string,string)() will create an empty array of Dictionary(Of String, String)

[mkankatala (Mahesh Kankatala)]

Hi @Jon_G

If you want to Initialize the Dictionary,

New Dictionary(Of String, String)

If you want to Initialize the List of Dictionary,

New List(Of Dictionary(Of String, String))()

Hope it helps!!

[ppr (Peter Preuss)]

@ppr

new Dictionary(Of string,string)() will create an empty array of Dictionary(Of String, String)

In addition to above, initialiing the array with an empty initialized empty Dictionary we can do

[Jon_G]

Thanks for the quick response, however still not having any luck with this, the syntax seems correct but I still see an error on the Assign activity. Not sure if my variable is wrong or something?

I’ve entered here: New Dictionary(Of string,string)()

Btw the reason I need multiple dictionaries is because I am parsing an API response which may include 1 or many payloads, so I need to put each payload into its own dictionary of key/value pairs.

[ppr (Peter Preuss)]

RnD and prototyping can be done within the immediate panel (as shown above)
Understanding the 6 Debugging Panels of UiPath in the easiest way possible! - News / Tutorials - UiPath Community Forum

About the exception, please share with us the Variable definition and modelling details

[V_Roboto_V]

Hello @Jon_G

Did you Declare the Array Dictionary Like this ?

If so, You have to intialize it like this:

New Dictionary(Of String, String)() {}

Screenshot from Variables Panel:

If this solves your issue, Do mark it as a solution
Happy Automation

[Jon_G]

My variable in the panel is displayed as:

System.Collections.Generic.Dictionary<System.String, System.String>

[V_Roboto_V]

Hi @Jon_G
Please check my solution

[Jon_G]

Thankyou! That works

The solution was so simple I was just missing both the brackets (){}

Great to know and hopefully this helps anyone else

[Jon_G]

Thanks this did also work if I was to store it as a List, however, I was able to follow a different solution to use Array still