How to get dynamically physical Xaml file name of currently running

uiautomation
studio

#1

I would like to get the name of the file name dynamically which is running in Uipath.

Example:

I’m invoking the Sample.Xaml file and there is exception inside this file ,In catch block calling ExceptionLog.Xaml, this file one of the parameter is “which file” caught the issue .How can I get the physical Xaml file name .


#2

I have a similar problem.
Did you find an answer?
I think filename should be accessible through System.Reflection but am not sure how…


#3

Did you check this?