Suppose I am running a file “test.xaml” file. I need to get that “test” as a output.
@kirti.iyer Following code gives your current work directory
assign a = System.IO.Directory.GetCurrentDirectory Following code gives file name assign a = a.Substring(a.LastIndexOf("\") + 1)
Hi. I implemented your code. But i am getting “Folder” as an output.
@kirti.iyer It is working for me. Try another way In the second assign activity
assign a = a.Split("\"c).Last
@kirti.iyer After first assign actvity use message box and see what all the values you are getting
In the code i mentioned after first assign activity it will give following result
For example F:\Uipath\Folder\CurrentXaml
After Second assign activity it will give only
@indra Hi. I am getting the directory path (D:\Folder) and current directory (Folder) but not the file name (test.xaml)
With your [GetCurrentXaml.xaml ],
If the number of [xaml] files is more than 2 ,
you can not catch which is just started in process.
Here we have a custom activity for it. Follow that thread and will give a try