How to convert argument type while invoking workflow

Help
1

how to convert string argument to int64 argument while invoking workflow from another workflow.
It is showing error as cannot change . when i change argument type in one workflow, it is not working as expected. Please help.

2

Hi @valli165,

you can use like this in the assign activity.

  intVar=Convert.ToInt64(StrVar)

Regards
Balamurugan.S

3

Thanks for the reply balupad14,…

I am trying that- not working as expected…

Throwing error that cant be changed.

4

What is the type of your target argument?

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image1263Ă—374 19.5 KB

5

target argument is int 64

6

What is the error can you please tell.

7

input string was not in correct format

8

is this the error?
Your input variable should be of type string. If its not do a input.ToString

9

Sure- will try this… Thank you!

10

I have one more doubt-i am using for each loop and joining string with ~.
strA=item.ToString.Trim()
strB=String.Join(“~”,strA.TrimStart,strB).TrimEnd
when running, - getting values like this-
value1 ~Value2 ~Value3

how to remove extra space here?

11

how have you declared stringB?
You dont need to trim again strA as you have already done it in line 1
also i think your logic should be:
strB=String.Join("~",strB,strA).Trim to get the correct output.

If you dont get the correct output do a trim of strB. But i think it wont be required.

12

Hi, Thanks for the help… the value is coming in one string - val1~Val2~Val3~
How to omit last character(~)
I want the value to be like this: Val1~Val2~Val3.

How to do that

13

You can use string.Remove(string.Length -1)

14

Its working… Thanks alot!

15

great!

{please close this thread marking the appropriate answer as solution}

16

i am quite new to it… please guide me on how to clos this Thread…

1 Like
17

Tick the answer that solved your issue like below

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image894Ă—78 2.71 KB

18

how to arrange the above string in ascending order?

19

what is your join formula?

20

strB=String.Join(“~”,strA.TrimStart,strB).TrimEnd