File Name Change

I’m reading a file with read activity whose file name changes every time when it downloads
like 1st time file name downloaded with name “response…12345…html”,
2nd time with name “response…4567…html”, etc first part is same that is “response” but remaining number varies every time… how to read this variable?

Hi @Aima_Arif,

If you want to get the files from the folder you can use
Assign activity as Stringarray variable = Directory.GetFiles(YourFolderPath)

So using for each activity you can loop into the String array and split the file name

Hope this may help you


I’m not reading from the folder
It downloads the link with above file names and then i have to read that file
The file name changes every time when it downloads

Is your bot downloading the file? If yes, you can use the Wait for Download activity. It will return the filename of the downloaded file in a variable you specify.


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Hi @Aima_Arif

str_filepath = Directory.GetFiles(yourfolder_path,“*.pdf”).OrderByDescending(Function(d) New FileInfo(d).CreationTime).ToList()(0)

Hope this might help you :slight_smile:


It gives index out of range exception for some files

Could you please share your screenshot?

in assign activity error comes
Index was out of range. Must be non negative and less than the size of collection

Hi @Aima_Arif

Check folder has any files or not. if the file is not present in the particular folder above error will throw.

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folder has downloaded file present there


ArrayOfString = Directory.GetFiles("FolderPath"."response*").OrderByDescending(function(x) File.LastModifiedTime(x)).ToArray()

This will give you all files with response as the starting of the name

And now first check if there are any values returned using ArrayOFString.Count >0

If yes then use ArrayOfString(0) to get the first file

ArrayOfString is avariable you need to create of type array of string

Hope this helps


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Hi @Aima_Arif Since the downloaded folder has the files you can use the below exp

Output var of type Array of Strings = Directory.Getfiles("FolderPath","*.yourfileextension")

Now use For Each to read the each file

This exp reads the files present in that folder irrespective of the file names

this helped
thank you so much:)

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Thank you :slight_smile:

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