I’m looking to extract only the numbers after this “=»”, but i keep having some other text too:
[^»]*[\d{1,}]$
login as: LOGIN SERVER@00.00.00.000’s password: Last login: Thu May 23
15:51:49 2019 from 00.00.00.000 CREER AUTANT DE REPERTOIRES SOUS
/NAME/NAME/NAME QU’IL Y A DE COMMERCANTS GERES. LE NOM DOIT ETRE LE NO
DE COMMERCANT. CREER ENSUITE SOUS CHACUN D’EUX UN REPERTOIRE NAME/
ps -fu NAME | grep exe | echo «resultat=»wc -l«resultat=»14
How do I solve this problem?
@rachrahul2 this aint helping, but thanks!
Buddy @mz3bel
use this expression buddy (remove the *)
[^»][\d{1,}]$
and you will get the value of 14 next to =>> as a second match
Cheers @mz3bel
Did that work buddy @mz3bel
@Palaniyappan, ok i see what you mean. There’s only a small problem, number 14 should change, so it’s like i need only the numbers after “=»”
Mean,…i didn’t get you buddy @mz3bel
@Palaniyappan number 14, can change from -1 to 15000. so i need the regex code to take all numbers after this “=»”
did that work buddy @mz3bel
Sorry for late response! No i doesn’t work on my side…
Characters in square brackets mean “one of these characters”, so it’s ? or » followed by a digit or { , 1 , , or } .
Positive lookbehind is the most useful here (match something that comes after X .)
(?<=something)thingIWantToMatch
So:
(?<=»)\d+
One or more digits preceded by a » , but don’t capture the »
Good to know that you managed to solve it 
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