Practice 3- Switch

Help Activities
, ,
1

Hi, Im new in Uipath so understand some steps are hard.

Im doing practice 3 - Switch in Variables, Data Types and Control Flow, but I don’t get completely 1 step( I try doing by myself but its hard because i dont know functions that are used in the solution, I guess it’s normal and in the future I will be capable to do it).

This is the solution:

Practice 3 Solution

  1. Create the first Array of strings variable with default value of {“Ax001”,“Ax002”,“Ax003”,“Ax004”,“Ax005”,“Bx001”,“Bx002”,“Bx003”,“Cx001”,“Cx002”,“Cx003”,“Cx004”}

  2. Create 3 Array of strings variables and instantiate them in the default by using new string(){}

  3. Use a ‘For Each’ loop to iterate through the initial array and:

  4. Use a ‘Switch’ inside the loop with the expression built to extract the first 2 letters using the ‘Substring’ method : item.Substring(0,2).ToLower

  5. For each of the 3 cases (“ax”, “bx”, “cx”), use the ‘Concat’ method to add the item to the corresponding Array: i.e. axArray.Concat({item}).ToArray

  6. Use 3 ‘Log Message’ activities to print the content of each of the 3 Arrays, by using the ‘String.Join’ method : i.e. string.Join(" ",bxArray).

All goes well except for I don’t understand how the program identifies exactly Ax, Bx or Cx.

I mean, you have your switch activity, default is done, ok, we go to the case ax that contain "axArray = axArray.Concat({item}).ToArray

When I read this, I understant that the variable “axArray” concat all the item variable, but actually it just add all Ax error, exclusively… That 's the part where I have problems to understand.

axArray.Concat ({item}). ToArray where this says to add only ax error?

2

Can you share your code ?

3

else you can ping me on sg2070156@gmail.com

4

"axArray = axArray.Concat({item}).ToArray

In Switch Activity, We have a condition in which we are getting First 2 value of each item and then based on ax , bx and cx it will divide and then added into array type variable.

image

1 Like
5

sorry, as a new user i can’t attach any file. and i tried to upload impr pant image but cannot too, sorry.

These images are from the solution .zip. I had deleted my code before your answer.

In the solution, there is a index variable located in the For each output Field but i don’t know exactlt its purpose

6

Yes, i understand that too, but how can discern from “Ax, Bx and Cx” ? item.substring(0,2) only select the first two value if im not wrong, but how can differentiate A, B and C? that is what i don’t get it .

and the “.ToLower” function is to lower case the variable yh? so it’s transform from “Ax” to “ax” and go on…

7

the name defined in “case” will be the filter later?

8

Switch Activity check automatically and it passes those item those cases condition is true like Case ax: check if item contain contain ax or not if yes then assign value into AxArray otherwise check same for bx or cx

1 Like
9

ok, perfect, thanks

10

Hi @AlvaroHG Thanks for bringing up this post, I have few doubts too.

@Sagar_Gupta1 your explanations are clear, thank you. below are my questions:

  1. in the expression item.Substring(0,2).ToLower what is the function of “0” and “2” , I understand 2 meaning it is extracting first two letter, but still I need some more clarity.

  2. in the expression axArray.Concat({item}).ToArray can you please help me understand why are we using round brackets “()” and flower brackets “{}”

I hope to hear from you soon, thank you.

Practice 3 - Switch.zip (11.7 KB)

11

Make the Default value for your Arrays: Ax, Bx and Cx = “new string(){}”. Just copy it into the Default box for each. This makes the arrays dynamic. The arrayname.concat({item}).ToArray assigns the Values to each item.

12

image
image1524×459 26.7 KB

Hi. Does somebody know why I get this compiler erro when trying to write this expression in the switch “loop”. ? How can this be fixed? :slight_smile:

13

Try this,

item.Substring(0,2).ToLower