Last two character is digit and alphabet

Input
122256A
456677AS
2345566B
456777DC
345556B
Output
True
False
True
False
True

Hi @Demo_User

How about this expression?

System.Text.RegularExpressions.Regex.IsMatch(YourString,"\d{2}\D{2}$")

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Regards
Gokul

Try this one @Demo_User

System.Text.RegularExpressions.Regex.IsMatch(YourString,"\d{2}\D{1}$")

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Hello

Try this in an ‘If’ activity:

System.text.regularexpressions.regex.IsMatch(yourStr,”\d[A-z]$”)

Then - ends with Digit and Alphabet
Else - does NOT end with digit and Alphabet

Hopefully this helps.

Cheers

Steve

input_str=“122256A”

in assign
Varibale=System.Text.RegularExpressions.Regex.IsMatch(Input_str,“[A-Z\d]{2}$”)
This Syntax returns ends true as it ends with Digit & Alphabet

if Varibale.equals(“True”)
then -True
else- False

How to remove special character only at the start and end of the text not in between somewhere

For this one you can create the new topic? @Demo_User

System.Text.RegularExpressions.Regex.Replace(YourString,"^[^a-zA-Z0-9]+|[^a-zA-Z0-9]+$","").ToString

image

Regards
Gokul

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