How to send a file attachment in the form-data parameter of the request to an API

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Hello Nagareetha,
In this video, I use multipart/form-data:

0:20 cURL example
1:35 Send the command from POSTMAN
2:50 Implement the code in C#
4:20 Run the code
4:50 Visual Basic code VB.NET
6:20 New Process on UiPath Studio with Invoke Code
7:20 Imports Libraries in UiPath Studio
8:30 Run the Robot to Upload and Download the file

Blockquote
Dim client As HttpClient = New HttpClient()
client.BaseAddress = New Uri(“YOUR URL”)
client.DefaultRequestHeaders.Accept.Clear()
client.DefaultRequestHeaders.Accept.Add(New MediaTypeWithQualityHeaderValue(“application/vnd.openxmlformats-officedocument.wordprocessingml.document”))
// for BASIC AUTH
Dim byteArray As Byte() = Encoding.ASCII.GetBytes(“username:password”)
client.DefaultRequestHeaders.Authorization = New AuthenticationHeaderValue(“Basic”, Convert.ToBase64String(byteArray))Dim byteArray As Byte() = Encoding.ASCII.GetBytes(“username:password”)
// for OAUTH2
client.DefaultRequestHeaders.Add(“authorization”, “Bearer YOUR TOKEN”)
Dim request As MultipartFormDataContent = New MultipartFormDataContent()
request.Add(New StringContent(“tags”), “Bad”)
request.Add(New StringContent(“displayreferencetext”), “true”)
request.Add(New StringContent(“similaritythreshold”), “0.63”)
request.Add(New StreamContent(File.OpenRead(“C:\8A.docx”)), “file”, (New FileInfo(“C:\8A.docx”).Name))
Dim response As HttpResponseMessage = client.PostAsync(“”, request).Result
Dim strm As Stream = response.Content.ReadAsStreamAsync.Result
Dim doc As Byte()
Dim ms As MemoryStream = New MemoryStream()
strm.CopyTo(ms)
doc = ms.ToArray()
File.WriteAllBytes(“C:\rpa\FORDOWNLOAD\rez.docx”, doc)

Thanks,
Cristian Negulescu