I want to extract the zip folder to the given path.
Thanks in advance,
What is the approach you have in your mind for this?
@jibanjyoti I have tried Invoke Method through compression.zipfile. But I am getting the error like, access to this path is denied.
Have you tried GUI automation for this?
- Keep the folder path+file name in one variable
- Open Zip application and provide the path using Uipath (Open Application and type into activity)
- Click on Extract Button and provide the full path of the target folder.
you may try “UnZip” activity from “BalaReva.Externals.Activities”
Now it is in new package.