how to split the single string from a group of string
for example; hai how are you is stoed in rc1 variable
I want only how are you from the sentence how to do it
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You can use the Split function for this, split with the space and take the first string.
- Assign -> Input = "hai how are you"
- Assign -> Output = Input.Split(" ").First
Hope it helps!!
In a ‘rc1’ variable the ‘hai how are you’ is stored
how to fetch only ‘how are you’ in that?
u can change the number accordingly.
Additionally,if you want to take first and last word u can follow this:strInput.Split(" “c).First and strInput.Split(” "c).last
System.Text.RegularExpression.Regex.match(“hai how are you” ,“(?<=hai\s).*”). Value.Trim
You can try this syntex for how are you
from group of words i want some words
example : hai how are you is stored in rc1
i want how are you only
Its very complicated, please simplify
Hi @anjani_priya
Try this:
rc1.Split({" "}, StringSplitOptions.None)(1) + " " + rc1.Split({" "}, StringSplitOptions.None)(2) + " " + rc1.Split({" "}, StringSplitOptions.None)(3)
Hope it hleps!!
If you need “how are you” you can try this
Input= "hai how are you”
Take assign activity
Rc1 = System.Text.RegularExpression.Regex.match(input,“(?<=hai\s).*”). Value.Trim
Note = rc1 you can keep variable type is system.string
Okay @anjani_priya
You can use remove function to remove this, we are using the split and remove function as well.
- Assign -> Input = "hai How are you"
- Assign -> Output = Input.Remove(0,Input.Split(" ").First.ToString.Length+1)
Hope you understand!!
Try this
Str="hai how are you"
Arr=Str.Split({" "c}, StringSplitOptions.RemoveEmptyEntries)
String.Join(" ", Arr.Skip(1))
Hope this helps!!
Then in that case follow this regex
System.Text.RegularExpressions.Regex.match(sttr,“(?<=hai).*”).tostring
The expression which you dont want to include will not be in the resultant output
the date 31 aug’2023 is there in rc1 , by split the split the date then how to replace that with 31-08-2023
rc1= “31 aug’2023”
DateTime.ParseExact(rc1, "dd MMM’yyyy", System.Globalization.CultureInfo.InvariantCulture).ToString("dd-MM-yyyy")
You can try this syntax it will work
DateTime.ParseExact(System.Text.RegularExpressions.Regex.Replace(rc1, "(st)", ""), "dd MMM’yyyy", System.Globalization.CultureInfo.InvariantCulture).ToString("dd-MM-yyyy")
output : -
how to get the string from the path of the file
Can you share the filepath sample and expected out