Retrieve a word in a line using regex

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1

Hi All,
I need to extract the word which is after ivf.This line may occur anywhere in the file.How can we do it

string:“The text is ivf road”
o/p road

2

Hi @ranjani,

Suppose this is your string

“The text is ivf road”
“The text is ivf bus”
“The text is ivf train”
“The text is ivf car”

Use the below regex

(?<=ivf )[A-Za-z]+

You can test it in https://regex101.com/

3

@ranjani,

str = "The text is ivf road”

Try this way: str.substring(str.IndexOf("ivf ")+"ivf ".length)

4

@ranjani Check attached zip file Regex.zip (10.3 KB)

5

Thanks for the link and it worked

6

Thanks for the file .I had also used the same pattern

7

Thanks for the reply

8

Also i have one more o/p in below format

state =er-fd-tr-tr delay

i need text between = and space

desired o/p:er-fd-tr-tr
I used below regex which gives me o/p:=er-fd-tr-tr delay
System.Text.RegularExpressions.Regex.Match(dynamic,“=(.*)\s”).Value

9

Use the below regex

(?<=[=])(.+?)(?=)

image

1 Like
10

Thank u so much

11

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