Open an application via shortcut

Help
1

Hello,

I have a question regarding opening an application via a shortcut

this is the target path of the shortcut to the app

“C:\Program Files (x86)\JDA\JDA Advanced Warehouse Replenishment\SIM.exe” trim

now the issue seems to be the trim part at the end as when i try to iput it to the filename on the ope aplication core it gives the following error

now thw shorcut wont work without the “trim” part and i cant figure out a way to open it in uipath

thanks for the help

2

Hi,
Don’t know why you used trim .
1.Here is the way to open the application
Right click on SIM.exe and send to desktop (to create a shortcut) then assign shortcut key ex(ctl+alt+s) then use send hotkey activity and pass the shortcut key it will launch your application.
2. Either use start process or open application and pass the "C:\Program Files (x86)\JDA\JDA Advanced Warehouse Replenishment\SIM.exe" in the property. I will work. :slight_smile:

3 Likes
3

use this insted
“C:\Program Files (x86)\JDA\JDA Advanced Warehouse Replenishment\SIM.exe”.trim

regards,
Vikas

1 Like
4

Hi,

I added the .trim at the end but all i get is this message saying that “an unamed file”

now, i went to the root folder where the .exe for the program is located and clicked on it and the same message

image.jpg919×743 178 KB

This is rather odd as thats where the shortcut is pointing to and opens up the program with no issues

5

thank you both,

after some tinkering i found the correct file to open the app and pointed uipath to it,turns out the app has an specific shortcut so i just created a short cut to that and it worked

Loving this software the more i use it

6

could you please help advise, why I should configure Selector?