I need to split the value before colon
For ex: 12/31/2006 work: output should be work
12/31/2006 work load:output should be work load
Try below expression:
yourString = β12/31/2006 work load:β
RequiredString = System.Text.RegularExpressions.Regex.Match(yourString.Split(":"c)(0),"[a-zA-Z]").Value
2 Likes
Hi, To get the outcome before colon, can use βSplitβ Function as shown in image,
To get outcome after colon can specify the array value as output(1)
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