generate 25 rand numbers between 50 5000

calc sum of odd numbers

cal sum of even numbers

print each rand num

at end

print the odd num sum

print the even num sum

You can use this to generate random numbers in a loop…if 25 is needed run loop for 25

`New Random.Next(50,5000)`

Cheers

You can use the following procedure to achieve the same:

→ Declare an integer array variable ‘randomNumbers’ and use this expression in the Assign activity:

`randomNumbers = Enumerable.Range(1, 25).Select(Function(x) New Random().Next(50, 5001)).ToArray()`

You can loop through the array & determine whether the number is odd or even. Based on the nature of the number, you can eventually sum & print them.

Hope this helps,

Best Regards.

Please find the below zip file to print random even and odd numbers and sum them up.

Random Numbers.zip (145.9 KB)

Hope it works for you!!

Regards,

HI,

Hope the following helps you.

```
rnd = New Random()
arrRndNumber = Enumerable.Range(0,25).Select(Function(i) rnd.Next(50,5001)).ToArray()
```

Then

Sum of even numbers

```
arrRndNumber.Where(Function(i) i mod 2 =0).Sum()
```

Sum of odd numbers

```
arrRndNumber.Where(Function(i) i mod 2 <>0).Sum()
```

Regards,

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