Get next line from regex

[RPA3]

Hello!
I have this:
Lalalala (alwaus this word)
12345.43 (always different, also: 453.12, 241241.24)
kflf;f;sdkfeeo
e34234
sfef

I need take: 12345.43
How I can do it?

[Seungwan (손승완)]

Hi, you can try this ‘\d+.\d{2}’ without the single quotation

[Yoichi]

Hi,

Can you try the following expression?

System.Text.RegularExpressions.Regex.Match(yourString,"(?<=Lalalala[\r\n]+).*").Value

Regards,

[RPA3]

@Yoichi

System.Text.RegularExpressions.Regex.Match(yourString,“(?<=Lalalala[\r\n]+).*”).Value

It is take all row

[RPA3]

It is not work for
Lalalala
34,231.31
fefwef

and for:
123.23

[Yoichi]

Hi,

Are parentheses data, not annotations? If so, the following will work.

System.Text.RegularExpressions.Regex.Match(yourString,"(?<=Lalalala[\r\n]+)[.,\d]+").Value

Regards,

[RPA3]

What if I have:
Lalala
1.
Lalalala
12.31

And I need 12.31. Now I have 1.

[Yoichi]

Hi,

Can you try the following?

System.Text.RegularExpressions.Regex.Matches(yourString,"(?<=Lalalala[\r\n]+)[.,\d]+").Cast(of Match).Last().Value

Regards

[RPA3]

@Yoichi

.Cast(of Match).Last().Value

Cast is not member of System.Text.RegularExpressions

[Yoichi]

hi,

Can you share your whole error message?
Do you use “System.Text.RegularExpressions.Regex.Matches” method?

Regards,