Good Day. What is the meaning of “0” in “Double.TryParse(InputValue, 0)”? Does “0” mean true? Thank you. Best regards, Robert Monsalud

Hi, According to official document, definition of Double.TryParse is the following. Public Shared Function TryParse (s As String, ByRef result As Double) As Boolean So, 2nd argument is ref type result. This means if input string can be parsed to double value, the result value is set to the result…

Double.TryParse(InputValue, 0) [meaning of 0]

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system (system) Closed December 16, 2022, 2:07am 4

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Double.TryParse(InputValue, 0) [meaning of 0]

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