hello
I want to cut the long stretched numbers by 10.
1234567890123456789012345678901234567890
=> 1234567890, 1234567890, 1234567890,1234567890
Like this!
What should I do?
hello
I want to cut the long stretched numbers by 10.
1234567890123456789012345678901234567890
=> 1234567890, 1234567890, 1234567890,1234567890
Like this!
What should I do?
Hi @bbbb,
You can use a Matches activity with the following Regex pattern:
\d{10}
Edit: This will give you an array of matches, if you need them in one string like you’ve specified then use the following:
String.Join(", ",YourMatches)
Hi,
I hope this will help you,
cutNumbers = Enumerable.Range(0, number.Length / 10).Select(Function(i) number.Substring(i * 10, 10)).ToList()
Now you can use the “Write Line” activity to display the contents of the “cutNumbers” list. Place this activity inside a loop to print each chunk separately.
For Each item In cutNumbers
Write Line activity: item
Next
Thank you
Hi @bbbb ,
With the Expression method :
Regex.Matches(strValue,"\d{10}").Cast(Of Match).Select(Function(x)x.Value).ToArray
Here, the assumption is you would require each 10 numbers as an item in the array.
Hello you can use Regex do to that.
TestSplit.xaml (6.2 KB)
when it is not guaranteed that the string length is always a multiple of 10 then we can handle this felxible as done below: